7-10p=-3p^2

Solution for 7-10p=-3p^2 equation:

7-10p=-3p^2

We move all terms to the left:

7-10p-(-3p^2)=0

We get rid of parentheses

3p^2-10p+7=0

a = 3; b = -10; c = +7;
Δ = b2-4ac
Δ = -102-4·3·7
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4}{2*3}=\frac{6}{6}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4}{2*3}=\frac{14}{6}
=2+1/3
$